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Back to category: Science Limited version - please login or register to view the entire paper. Enzyme Lab Discussion: 1. Baseline value for H2O2 = |(final burette reading – initial reading)| = |(6.9mL – 10mL)| = |-3.1mL| = 3.1mL By subtracting the initial reading from the final burette reading and then taking the absolute value of the value, you would get the baseline value, which is 3.1mL 2. The percent of H2O2 that spontaneously decomposes in 24 hours = mL baseline – mL 24 hours X 100 mL baseline = 4.1mL – 3.4mL X 100 4.1mL = .7mL X 100 4.1mL = 70% 4.1mL = 17.1% Thus, the percent of H2 O2 that spontaneously decomposes in 24 hours is 17.1%. 3. The amount of H2O2 used for each reaction time = (Baseline value – amount of KMnO4 used) Sample: ... Posted by: Darren McCutchen Limited version - please login or register to view the entire paper. |
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